Lymecycline Capsules
Action and use
Tetracycline antibacterial.
Definition
Lymecycline Capsules contain Lymecycline.
Content of lymecycline, C29H38N4O10
90.0 to 110.0% of the stated amount.
Identification
The contents of the capsules comply with the following tests.
6 volumes of water, 35 volumes of methanol and 59 volumes of dichloromethane.
The test is not valid unless the chromatogram obtained with solution (3) shows three clearly separated spots.
The principal spot in the chromatogram obtained with solution (1) corresponds in position, colour and size to that in the chromatogram obtained with solution (2).
Tests
Dissolution
Carry out the procedure protected from light. Comply with the requirements for Monographs of the British Pharmacopoeia in the dissolution test for tablets and capsules, Appendix XII B1.
Calculate the total content of lymecycline, C29H38N4O10, in the medium from the absorbances obtained and using the declared content of C22H24N208,HCl in tetracycline hydrochloride BPCRS. Each mg of C22H24N208,HCl is equivalent to 0.9241 mg of C22H24N208 (tetracycline). Multiply the content of tetracycline by 1.356 to obtain the content of lymecycline.
Free tetracycline
Not more than 2.5%, when determined by the following method. To a quantity of the contents of the capsules containing 0.5 g of Lymecycline add 50 mL of butyl acetate and allow to stand at 25° for 1 hour. Filter (Whatman GF/C is suitable) and extract the filtrate with two 25-mL quantities of 0.1m hydrochloric acid. Combine the extracts, add sufficient 0.1m hydrochloric acid to produce 50 mL and dilute 10 mL of this solution to 100 mL with 0.1m hydrochloric acid. The absorbance of the resulting solution at the maximum at 355 nm, Appendix II B, using 0.1m hydrochloric acid in the reference cell, is not greater than 0.64.
Related substances
Carry out the method for liquid chromatography, Appendix III D, using the following solutions prepared immediately before use.
When the chromatograms are recorded under the prescribed conditions, the retention time of tetracycline is about 8 minutes. The retention times relative to tetracycline are: impurity E, about 0.50; impurity A, about 0.6; impurity F, about 0.68; impurity B (eluting on the tail of the principal peak), about 1.2; impurity D, about 1.45; impurity G, about 1.45; impurity C, about 2.95.
Weigh 80.0 g of 2-methyl-2-propanol and transfer to a 1000 mL volumetric flask with the aid of 200 mL of water. Add 100 mL of a 3.5% w/v solution of dipotassium hydrogen orthophosphate adjusted to pH 8.0 with dilute orthophosphoric acid, 200 mL of a 1% w/v solution of tetrabutylammonium hydrogen sulfate adjusted to pH 8.0 with dilute sodium hydroxide solution and 10 mL of a 4% w/v solution of sodium edetate adjusted to pH 8.0 with dilute sodium hydroxide solution; dilute to 1000 mL with water.
The test is not valid unless, in the chromatogram obtained with solution (6):
the resolution between the peaks due to impurity A (first peak) and tetracycline (second peak) is at least 3.0;
the resolution between the peaks due to tetracycline and impurity D (third peak) is at least 5.0;
the symmetry factor of the peak due to tetracycline is not more than 1.25.
In the chromatogram obtained with solution (1):
the area of any peak corresponding to impurity A is not greater than 1.6 times the area of the corresponding peak in the chromatogram obtained with solution (7) (8%);
the area of any peak corresponding to impurity C is not greater than twice the area of the corresponding peak in the chromatogram obtained with solution (7) (2%);
the area of any peaks corresponding to impurities E and F are not greater than 0.4 times the area of the peak corresponding to impurity A in the chromatogram obtained with solution (7) (2% each);
the area of any peak with a retention time relative to tetracycline of about 1.6 is not greater than 0.14 times the area of the peak corresponding to impurity A in the chromatogram obtained with solution (7) (0.7%);
the area of any peak corresponding to impurity B is not greater than 0.1 times the area of the peak corresponding to impurity A in the chromatogram obtained with solution (7) (0.5%);
the sum of the areas of any peaks corresponding to impurities D and G is not greater than the area of the peak corresponding to impurity D in the chromatogram obtained with solution (7) (0.5%);
the area of any other secondary peak is not greater than 0.1 times the area of the peak corresponding to impurity A in the chromatogram obtained with solution (7) (0.5%);
the sum of the areas of all the secondary peaks is not greater than 2.2 times the area of the peak corresponding to impurity A in the chromatogram obtained with solution (7) (11%).
Disregard any peak with an area less than the area of the peak corresponding to impurity A in the chromatogram obtained with solution (8) (0.1%).
Water
The contents of the capsules contain not more than 7.0% w/w of water, Appendix IX C. Use 0.1 g.
Assay
Carry out the method for liquid chromatography, Appendix III D, using the following solutions prepared immediately before use.
The chromatographic conditions described under Related substances may be used.
Inject solution (2) six times. The Assay is not valid unless the relative standard deviation of the area of the principal peak is at most 1.0%.
Calculate the content of C29H38N4O10 in the capsules using the declared content of C22H24N208,HCl in tetracycline hydrochloride BPCRS. Each mg of C22H24N208,HCl is equivalent to 0.9241 mg of C22H24N208 (tetracycline). Multiply the content of tetracycline by 1.356 to obtain the content of lymecycline.
Impurities
The impurities limited by the requirements of this monograph include impurities A to G listed under Lymecycline.
204 mg of Lymecycline is equivalent to approximately 150 mg of tetracycline.